Your friend says that a convenient way to draw a equilateral triangle on a coordinate plane is with the base along the x-axis starting at the point (0,0) is your friend correct explain your reason

He's half right.

Step-by-step explanation:

So far so good. You will have the length of the base where it belongs and correct. The problem is that you are not finished. How does he suggest you draw the other two lines?

One way is to draw the perpendicular bisector to the from the midpoint of the base line. The perpendicular bisector is sqrt(3)/2 * the length of the base.

He's about 1/2 right.

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step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )