Being 360 meters apart, two dogs started running towards each other at the same time. in 20 seconds the distance between them was 200 meters. how fast each of them ran if one of them ran faster by 3 meters per second?

Speed of one dog is 2.5 m/s and other dog is 5.5 m/s.

Step-by-step explanation:

Total distance between the two dogs = 360 m

Let the speed of one dog be x m/s, then the speed of second dog will be x+3 m/s.

Then total speed of two dogs = x+x+3 = 2x+3

Times = 20 seconds

After 20 seconds, distance left between them = 200 m

Distance traveled by the two dogs in 20 seconds = 360 m - 200 m

                                                                                    = 160 m

We know, Speed  =

          2x+3 =  

              2x = 8-3 = 5

              x =  2.5 m/s

Speed of first dog = 2.5 m/s

Speed of second dog = x+3 = 2.5 +3

                                     = 5.5m/s

Speed of one dog is 2.5 m/s and other dog is 5.5 m/s.

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl