Which system below has no solution? 1. y = 4x and y = 2x - 3 2. y = -4x and y = 2x - 3 3. y = -4x and y = 2x + 3 4. y = -4-x and y = 2x - 3

None of these options has "no solution"

Step-by-step explanation:

we will verify each options

(1)

y = 4x and y = 2x - 3

we can set them equal and solve for x

Since, solutions exists

so, this is FALSE

(2)

y = -4x and y = 2x - 3

we can set them equal and solve for x

Since, solutions exists

so, this is FALSE

(3)

y = 4x and y = 2x+ 3

we can set them equal and solve for x

Since, solutions exists

so, this is FALSE

(4)

y = -4-x and y = 2x - 3

we can set them equal and solve for x

Since, solutions exists

so, this is FALSE

So, No system of equations have no solution

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100

ummm seems that u didnt post the attachement !