What is the probability of rolling an even number and then an odd number when rolling two number cubes? size of sample spaces = a)6 b)12 c)30 d)36 number of desired outcomes = a)3 b)6 c)9 d)18 p(first is even and second is odd) = a)1/36 b)1/12 c)1/4 d)1/2

•Size of sample spaces= 36.

•Number of desired outcomes=9.

•P(first is even and second is odd)=1/4.

•To hard ???- 1st answer is D. 2nd answer is C. 3rd answer is C.

•Still too hard ;-;???- 1st answer is 36. 2nd answer is 9. 3rd answer is 1/4.

This is the best I could help , hope this will get you a ✅.♡

Step-by-step explanation:

Just did it ^-^

1) Option D - 36

2) Option C - 9

3) Option C-

Step-by-step explanation:

Given : Two dice are rolled and outcome is an even number and then an odd number.

To find :

1)Size of sample spaces

When two dice are rolled total no. of outcomes are  

Therefore, Option D is correct - 36

2)Number of desired outcomes

Condition is first come even than odd on a dice

Favorable outcomes = (2,1),(4,1),(6,1),(2,3),(4,3),(6,3),(2,5),(4,5),(6,5)

Number of desired outcomes is 9

Therefore, Option C is correct- 9

3)P(first is even and second is odd)

Favorable outcomes =  (2,1),(4,1),(6,1),(2,3),(4,3),(6,3),(2,5),(4,5),(6,5)

Total no. of outcomes = 36

Therefore, Option C is correct -

idk lol

step-by-step explanation:

14

step-by-step explanation:

14 x 3 = 42