Triangle xyz is translated 4 units up and 3 units left to yield δx'y'z'. what is the distance between any two corresponding points on δxyz and δx'y'z′? a. units b. 5 units c. 7 units d. 25 units

option B. 5 units.

Step-by-step explanation:

If a Δ XYZ is translated 4 units up and 3 units left to yield X'Y'Z'.

If we consider one vertex  X (x, y) of the triangle XYZ then after translation X will form new vertex as

x' (x-3, y-4)

Then we have to find the distance between x and x' after translation.

In the figure attached we have to find the distance a.

a² = 3² + 4² ( By Pythagoras Theorem)

a² = 9 + 16

a = √25 = 5 units

Therefore, answer will be option B. 5 units.

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation:

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step-by-step explanation:

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