Given: in triangle abc, ∠b ≅ ∠c prove: ab ≅ ac complete the paragraph proof. we are given that ∠b ≅ ∠c. assume segment ab is not congruent to . if ab > ac, then m∠c > m∠b by the . if ab < ac, then m∠c < m∠b by the converse of the triangle parts relationship theorem. but by the definition of congruent, we know the measure of angle b equals the measure of by the given statement. therefore, we have a contradiction: ab = ac, and ab ≅ ac.

AB ≅ AC

Step-by-step explanation:

Given information: In triangle ABC, ∠B ≅ ∠C.

To prove: AB ≅ AC

Let us assume side AB is not congruent to side AC.

If AB > AC, then ∠B < ∠C ( By the converse of the triangle parts relationship theorem ).

If AB < AC, then ∠B > ∠C ( By the converse of the triangle parts relationship theorem ).

It is given that ∠B ≅ ∠C, so by the definition of congruent segment.

Therefore, we have a contradiction:

AB = AC

By the definition of congruent segment.

AB ≅ AC

Hence proved.

well the 1 and -1 are always after the 0 and the 0 is inthe middle. s thats what i would guess. but i dont know what a slope of 2 is sorry

step-by-step explanation:

51-50

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