One root of f(x)=x^3+10x^2-25-250 is x = –10. what are all the roots of the function? use the remainder theorem. x = –25 or x = 10 x = –25, x = 1, or x = 10 x = –10 or x = 5 x = –10, x = –5, or x = 5

All zeros are

x=-10 , x=-5 , x=5

Step-by-step explanation:

we are given function as

we are given one of zero is x=-10

we have to use Remainder theorem

we can find all possible factor of 250

so, we will check zeros at x=-5 and x=5

At x=-5:

we can plug x=-5

At x=5:

we can plug x=5

So, other zeros are

x=-5 and x=5

All zeros are

x=-10 , x=-5 , x=5

D

Step-by-step explanation:

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation:

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

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