Where are the asymptotes for the following function located? (fx)-7/x^2-2x-24

Vertical aymptotes at x= -4 and x=6

horizontal asymptote at y=0

Step-by-step explanation:

To find out vertical asymptote we take the denominator =0 and solve for x

x^2-2x-24=0

sum = -2  and product = -24

4 * (-6) = -24

4 - 6 = -2

(x+4)(x-6)=0

Now we set each factor =0 and solve for x

x+ 4=0                   and               x-6=0

x= -4                      and                 x=6

Vertical aymptotes at x= -4 and x=6

Now we find horizontal asymptote

The degree of numerator is 0

degree of denominator is 2

Degree of numerator is less than the degree of denominator then horizontal  asymotote is y=0

0 < 2 so horizontal asymptote at y=0

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560