How do you substitute 3x-12y=-6 and x-4=-8?

x - 4 = -8      add 4 to both sides

x = -4

Put the value of x to the first equation 3x - 12y = -6:

3(-4) - 12y = -6

-12 - 12y = -6         add 12 to both sides

-12y = 6       divide both sides by (-12)

y = - 0.5

New question:

x - 4y = -8       add 4y to both sides

x = 4y - 8

Substitute it to the first equation:

3(4y - 8) - 12y = -6       use distributive property

(3)(4y) + (3)(-8) - 12y = -6

12y - 24 - 12y = -6

-24 = -6     FALSE

20

step-by-step explanation:

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step-by-step explanation: