Find the equation of a line that passes through the given points(0,2) and (6,2)

y=2

Step-by-step explanation:

To write the equation of a line we must have a slope and a point. To find the slope we use the slope formula and substitute (x,y) points in it as shown below:

Since the slop is 0, this is a horizontal line of the form y=b. B is the y-intercept of the points on the line. Notice that both are 2? y=2

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

40 x 50 = 2000

step-by-step explanation: