Due to smoking, a terminally ill patient loses his lung capacity approximately 2% every 4 months. at this rate, beginning at 100% capacity, what will the patient's lung capacity be in one year?

94.1%

Step-by-step explanation:

Convert that 100% to "1."  Then:

Lung capacity as a decimal fraction) = C(x) = 1(1.00-0.02)^x, where x represents the number of 4-month periods.

After the first 4-month period, the lung cap should be 1(1.00-0.02)^1, or 0.98.

After the 2nd 4-month period, 1(0.98)^2, and

After the 3rd 4-month period, 1(0.98)^3, or 0.941

After 1 year (which is after three 4-month periods), the patient's lung cap has declined to 0.941 of its former maximum value (1), or 100%.  0.94 is equivalent to 94.1%.

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.