Two bags both contain blue marbles and green marbles. bag a contains 6 blue marbles and 4 green marbles and bag b contains 2 blue marbles and 3 green marbles. a marble is drawn from each bag. what is the probability that both marbles are green?

6/25

Step-by-step explanation:

Total marbles in Bag A = 6 blue + 4 green = 10 marbles.

Total marbles in Bag B = 2 blue + 3 green = 5 marbles.

P(Green marble is drawn from Bag A) = Green Marbles/Total Marbles = 4/10.

P(Green marble is drawn from Bag B) = Green Marbles/Total Marbles = 3/5.

Assuming that both the above probabilities are independent, therefore:

P(Both marbles are green) = 4/10 * 3/5 = 12/50 = 6/25.

Hence, the probability is 6/25!!!

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

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step-by-step explanation: