The perimeter of a parallelogram must be no less than 40 feet. the length of the rectangle is 6 feet. what are the possible measurements of the width? write an inequality to represent this problem. use w to represent the width of the parallelogram. [hint: the formula for finding the perimeter of a parallelogram is p = 2l + 2w. what is the smallest possible measurement of the width? justify your answer by showing all your work.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

it would be:

c.parallelogram.