The polynomial x 3 + 5x 2 - ­57x -­189 expresses the volume, in cubic inches, of a shipping box, and the width is (x+3) in. if the width of the box is 15 in., what are the other two dimensions? ( hint: the height is greater than the depth.)

The other two dimensions are either (x+9) or (x-7). other two dimensions are either 21 inches  or 7 inches.

Step-by-step explanation:

The volume is defined by the function.

The width is (x+3).

Using synthetic or long division method divide by (x+3).

The volume of cuboid is

Therefore other two dimensions are either (x+9) or (x-7).

If the width is 15 inches, then

The other two dimensions are

Therefore other two dimensions are either (x+9) or (x-7). other two dimensions are either 21 inches  or 7 inches.

Other two dimensions are 21 and 5.

Height = 21 in.

Depth = 5 in.

Step-by-step explanation:

Since we have given that

As we have given that

Width = x+3

That means

So, by dividing, x^3 + 5x^2 -57x-189 by x+3 we get,

Noe, we split the quadratic equation:

So, as we have given that

Width = 15

So, other two dimensions are 21 and 5.

Height = 21 in.

Depth = 5 in.

529 and 531

step-by-step explanation: