Quadrilateral pqrs is inscribed in circle a. which statement is necessarily true? a. m∠r = m∠sb. m∠r + m∠s = 180°c. m∠r = m∠sd. m∠r + m∠s = m∠p + m∠q

(B) m∠R+m∠S=180°

Step-by-step explanation:

The quadrilateral is inscribed in circle A, then m∠R+m∠S=180° as the sum of corresponding angles of a quadrilateral is equal to 180°.

Since, ∠R and ∠S are corresponding angles of the quadrilateral, therefore, they ca't be equal. Hence, ∠R≠∠S.

Also, the sum of all the angles of the quadrilateral is equal to 360°, therefore ∠P+∠Q+∠R+∠S=360°, hence ∠R+∠S≠∠P+∠Q

Therefore, option B is correct.

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere