Given (0,1) and (2, 4). the slope between the two points is the equation of the line through the two points isan air balloon begins its descent to the ground at 1000 ft above the ground and falls at a rate of 50 ft per minute. select all that apply to this situation. the y-intercept is 50 ft. the balloon falls at a rate of 50 ft per minute. the slope is 1000 ft per minute. the balloon is falling at 1000 ft per minute. the y-intercept is 1000 ft. the balloon begins to from an initial height of 1000 ft. it will take the balloon 20 minutes to reach the ground. the slope is -50 ft per minute. the balloon is falling at 50 ft per minute.

we select all the points apply to the given situation:

(a)The balloon falls at a rate of 50 ft per minute.

(b)The y-intercept is 1000 ft.

(c)The balloon begins to from an initial height of 1000 ft.

(d)It will take the balloon 20 minutes to reach the ground.

(e)The slope is -50 ft per minute.

Step-by-step explanation:

We have given,

Two points (0,1) and (2,4).

Slope of line passing through these two points is:

Slope =

Next,

A balloon begins its descent to the ground at 1000 ft above the ground.

that means y intercept = 1000 ft

And Balloon falls at a rate of 50 ft per minute.

Time taken to reach the ground = = = 20 minutes

Since the balloon is falling down so the distance along y axis will decrease. Hence the slope will be negative and equal to - 50 ft per second

Now we select all the points apply to the given situation:

(a)The balloon falls at a rate of 50 ft per minute.

(b)The y-intercept is 1000 ft.

(c)The balloon begins to from an initial height of 1000 ft.

(d)It will take the balloon 20 minutes to reach the ground.

(e)The slope is -50 ft per minute.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

because that’s us why