In the diagram, point o is the center of the circle and m∠adb = 43°. if m∠aob = m∠boc, what is m∠bdc? a. 45°b. 43°c. 41°d. 37°e. 33°

m∠BDC = 43°

Step-by-step explanation:

According to the theorem every peripheral angle in the circle is equal to half value of central angle.

Angle m∠ADB is corresponding peripheral angle of central angle m∠AOB.

According to this m∠AOB = 2· m∠ADB = 2· 43 = 86°

If angle m∠BOC=m∠AOB= 86°

Angle m∠BDC is corresponding peripheral angle of central angle m∠BOC

According to this m∠BDC = m∠BOC/2 = 43°

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