Ben was walking in manhattan at a constant speed. he went along 5th avenue from 4th to 98th street. at 3: 00 he was on 15th street, and at 4: 30 he was on 45th street. when did he start and when did he finish his walk? write an equation which could tell on what street n he was t minutes after he started to walk.

The starting time is 2:27 and finishing time is 7:09.    

Step-by-step explanation: It is given that Ben started from 4th street and he finished at 98th street.

Also, at 3:00, he was on 15th street and at 4:30, he was on 45th street.

That is, time taken to cover (45-15), i.e., 30 streets is 90 minutes,                           so the time taken to cover 1 street is 3 minutes.

Therefore, Ben covers distance from one street to second in 3 minutes. Since he started from 4th street, and there are 11 streets to cover between 4 and 15, so Ben's starting time was (3:00 - 3×11 min) = 2:27.

And his finishing time was (4:30 + 3×53 min) = 7:09.

Again, the equation that tells us on what street 'N' he was after time 'T' of his starting can be written as

Thus, the starting and finishing time was 2:27 and 7:09 respectively.

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

attachment?

step-by-step explanation: