Me find x and y for this problem plz

x = 8 and y = -1.

Step-by-step explanation:

b^x / b^y = b^9

By the law of indices:-

b^(x - y) = b^9

therefore x - y = 9(1) . Also:

(b^x * b^2) / b^3y = b^13

b^(x + 2) / b^3y = b^13

b^(x + 2 - 3y) = b^13

Therefore x + 2 - 3y = 13(2)

From equation (1)  y = x - 9 so substituting in equation 2:

x + 2 - 3(x - 9) = 13

x + 2 - 3x + 27 = 13

-2x = 13 - 2 - 27 = -16

x = 8

and from equation (1) y = 8-9 = -1

d i think

step-by-step explanation: