Write an equation of the line, in standard form, that passes through the points (-2,2) and (4,5). show all work for credit

x - 2y = - 6

Step-by-step explanation:

the equation of a line in standard form is

Ax + By = C (A is a positive integer and B, C are integers

To begin find the equation in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

To calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 2, 2) and (x₂, y₂ ) = (4, 5)

m = = = , hence

y = x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (- 2, 2), then

2 = - 1 + c ⇒ c = 2 + 1 = 3

y = x + 3 ← in slope- intercept form

multiply through by 2

2y = x + 6 ( subtract 2y from both sides )

0 = x - 2y + 6 (subtract 6 from both sides )

x - 2y = - 6 ← in standard form

5050

hope this !

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a