Acircle with center c (4,-2) contains the point d (8,1). what is the equation of the line perpendicular to the radius of the circle passing through point c?

Step-by-step explanation:

A circle with center C (4,-2) contains the point D (8,1).

Lets find out the slope of the line that contains point C  and D

Slope =

C (4,-2) is (x1,y1)  and  D (8,1) is (X2,y2)

Slope =

To get slope of perpendicular line we take negative reciprocal of 3/4 that is -4/3

the line passes throught point C

m= -4/3   , point (4,-2)

Use point slope formula

y-y1=m(x-x1)                x1= 4, y1= -2, plug in all the values

Subtract 2 on both sides

mx+89b(-98)nb

step-by-step explanation: