Given the graph of square quad and its reflection. use the coordinates of the images' vertices, d and d' to algebraically find the line of reflection. in your final answer include all of your work.

x = 0

Step-by-step explanation:

D = (-8, -3), D' = (8, -3)

The line of reflection is the perpendicular bisector of the segment between these points. In order to find that, we need to know the slope and midpoint of the segment DD'.

Slope

The slope of the line DD' is ...

... m = (change in y)/(change in x) = (-3 -(-3))/(8 -(-8)) = 0/16 = 0

The line through point D with slope  0 is ...

... y = 0(x -(-8)) +(-3)

... y = -3

Midpoint

The midpoint of the segment DD' is the average of their coordinates:

... M = (D +D')/2 = ((-8, -3) +(8, -3))/2 = (-8+8, -3-3)/2 = (0, -3)

Perpendicular bisector

The line perpendicular to the horizontal line y=-3 through the point M = (0, -3) will be a vertical line of the form ...

... x = constant

The x-coordinate of the point (0, -3) tells us the constant, so the line of reflection is ...

... x = 0

step-by-step explanation:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3