Δabc is dilated by a scale factor of 0.25 with the origin as the center of dilation, resulting in the image δa′b′c′. if a = (-1, -5), b = (2, 1), and c = (14, 17 ), what is the length of b'c'? select one: a. d = 15.25 b. d = 20 c. d = 5 d. d = 15

  c.  d = 5

Step-by-step explanation:

The difference in coordinates B and C is (14, 17) -(2, 1) = (12, 16). When the figure is scaled by 0.25, that difference becomes ...

  0.25(12, 16) = (3, 4)

The length of a line segment with those coordinate differences is ...

  d = √(3² +4²) = √25 = 5 . . . . matches selection c.

alot

step-by-step explanation:

its a wood chuck that can chuck wood

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2