The rectangle shown has a perimeter of 40cm and the given area of 64 cm squared it's length is 8 more than twice its width write and solve a system of equations to find the dimension of the rectangle

16 = l

4 = w

Step-by-step explanation:

{64 = wl

{40 = 2w + 2l

{l = 8 + 2w

64 = w[8 + 2w] ↷

-64 + 8w + 2w² ↷

[2w² - 8w] + [16w - 64]

2w[w - 4] 16[w - 4]

[w - 4][2w + 16] = 0

↑

This is the expression we want because when we talk about dimensions, we want NON-NEGATIVE numbers. The other expression results in -8 = w, and we do not want that; this expression gives us a solution of 4 = w, and THIS is exactly what we want. Anyway, you plug "4" back into the system of equations and you will get a length of 16 centimetres.

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step-by-step explanation:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.