What is the equation of the following line written in slope-intercept form? y = x - 13/3 y = x - 13/3 y = -x - 13/3

y = -2/3 x - 13/3

Step-by-step explanation:

We have one point at (-5,-1)  and there is another point at (1,-5)

The slope is

m= (y2-y1)/(x2-x1)

   = (-5--1)/(1--5)

  = (-5+1)/(1+5)

  = -4/6

=-2/3

The point slope form of the equation is

y-y1 = m(x-x1)

y--1 = -2/3(x--5)

y+1 =-2/3( x+5)

Distribute

y+1 = -2/3 x -10/3

Subtract 1 from each side

y +1-1 = -2/3 x -10/3 -1

Get a common denominator

y = -2/3 x -10/3 -3/3

y = -2/3 x - 13/3

the answer is d. (1.2, -4.7) on edgn

hope this !

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: