8−i3−2i if the expression above is rewritten in the form a+bi, where a and b are real numbers, what is the value of a? (note: i=−1)

8

Step-by-step explanation:

somewhat confusing Q...going w wat the OP said in comments: i3 is i x 3, then it becomes 8 - ix3 - 2i

= 8 - 5i

so a = 8

a=8

Step-by-step explanation:

8−i3−2i

= 8-(3+2)i

=8-5i

in the form of a+bi

a=8

b=-5

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