If (6^2)^x =1 what is the value of x

x = 0

Step-by-step explanation:

Rewrite (6^2)^x =1 as 6^(2x) = 1.

Next, take the logarithm (common or natural) of both sides, obtaining

2x log 6 = log 1

2x log 6 = 0

Then x = 0.

Note that (6^2)^0 = 1, since any positive number raised to the prower 0 is 1.

a

step-by-step explanation:

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.