What is the probability of rolling a 6 and then a 1 on consecutive rolls of a standard, 6-sided number cube?

Hello from MrBillDoesMath!

1/36

Discussion:

The events of are unrelated ("mutually exclusive") so the probability of both happening is the product of the individual probabilities.  That is,

(1/6) * (1/6) = 1/36

Thank you,

MrB

1/36 chance

Step-by-step explanation:

You find the probability by finding the amount of the number you roll over the total choices that you can roll. In this example, there is one 6 on the dice and there are 6 different possibilities of numbers you can roll. That means the probability of rolling a 6 is 1/6. It would be the same if you were rolling a one because there is one 1 on the dice and there are 6 different possibilities of numbers you can roll. You would multiply each probability to find the probability of rolling both numbers. 1/6 * 1/6 is equal to 1/36, therefore, that is the probability of rolling a 6 and then a 1.

answer: for each 3 girls there is 2 boys . 3: 2

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walter needs to make at least 5 more cookies but no more than 40. 5 ≥ x ≥ 40;

step-by-step explanation:

walter has to make a minimum of 20 cookies. he already has 15 cookies made, so he must make 5 more to meet the minimum.

the maximum amount of cookies he can make is 55. he already has 15, so he has to make no more than 40 more cookies to meet the maximum.