Alguien que me ayude a derivar √3x su solución es √3/2√x

Hello from MrBillDoesMath!

(3 /2)* ( x^(1/2) )

Discussion:

I think you are asking for the derivative of  (3x) ^ (1/2)  -- the square root of both 3 and x.  

The derivative of (3x) ^ (1/2) is

(1/2)  (3x) ^ (1/2 -1)   (d(3x)/dx) =

(1/2) (3x)^(-1/2)  3 =

3/2  (1/ (3x)^ (1/2) ) =

3/2 (  1/ 3^(1/2)) ( 1 / x^(1/2) ) =

(3/3^(1/2))  * (1/2) ( 1/ x^(1/2) ) =

(  3^(1/2) / 2 )  *  (1/ x^(1/2) ) =

(  3^(1/2) ) *  (1 / 2) *  (1/  x^(1/2) ) =

It's straightforward but using a keyboard over complicates its appearance

Thank you,

MrB

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!