This graph shows the water level in a bathtub, in inches, over time (in minutes). what situation could match the graph? a. alison turns on the water and allows it to run in the tub for a few minutes. then she decides the water is too hot and allows some of the water to drain out of the tub before filling it up the rest of the way. after the tub is full, alison takes a short bath. after the bath, alison allows the water to completely drain from the tub. b. alison empties the water from the tub and then fills it halfway up again. she allows the water to sit for a couple of minutes and then checks to see if it is at the right temperature. it is a little hot, so she adds some more cold water to the tub. she takes a short bath and then allows half of the water to drain from the tub. c. alison turns on the water and allows it to run in the tub for a few minutes. she then turns the water off while she runs to answer the front door. alison comes back and allows water to run into the tub for a couple more minutes before she takes a short bath. after the bath, alison allows the water to completely drain from the tub. d. alison turns on the water and allows it to fill the tub. she then takes a short bath. after her bath, she allows the water to drain from the tub. after a couple of minutes, the drain gets stopped up with a washcloth and the water does not drain for a couple of minutes. alison removes the washcloth and the rest of the water drains from the tub. graph:

The situation that would match the graph would be letter C.

Step-by-step explanation:

The answer would be C because you can see in the graph that it starts at 0 and she allows it to fill then stops. In the graph you can see how for a few minutes the water is at the same height. After this the amount of water increases once again in the graph and then stays for a few minutes which is when she was bathing. Lastly, you can see the amount of water decrease back to 0 which is when she empties it out completely.

perimeter of the first rectangular board is 9 feet.

step-by-step explanation:

let p = perimeter of first board.

l = length of first board

w = width of first board

length of first board = 2 * width of first board - 3

l = 2w - 3

perimeter of first board = 2l + 2w

since l = 2w-3, then

p = 2*(2w-3) + 2w which equals 4w-6 + 2w which equals 6w-6

length and width of the second board are reciprocals of corresponding length and width of the first board.

length of second board = 1/(2w-3)

width of second board = 1/w

perimeter of second board is 1/5th perimeter of the first board.

perimeter of second board = p/5

perimeter of the second board = (2/(2w-3) + 2/w)

since the perimeter of the first board is 5 times the perimeter of the second board, this means that:

6w-6 = 5*(2/(2w-3) + 2/w)

which is the same as:

6w-6 = (10/(2w-3) + 10/w)

if we multiply both sides of this equation by (2w-3), we get:

(6w-6)*(2w-3) = 10 + 10*(2w-3)/w

if we multiply both sides of this equation by w, we get:

(6w-6)*(2w-3)*w = 10*w + 10*(2w-3)

we can simplify this to become:

(6w-6)*(2w-3)*w = 10w + 20w - 30

which becomes:

(6w-6)*(2w-3)*w = 30w-30

if we divide both sides of this equation by (6w-6), we get:

(2w-3)*w = (30w-30)/(6w-6)

which becomes:

(2w-3)*w = 5

this can be simplified to:

2w^2 - 3w = 5

subtract 5 from both sides of this equation to get:

2w^2 - 3w - 5 = 0

which can be factored into:

(2w-5)*(w+1) = 0

which makes:

w = 5/2

or

w = -1.

w can't be negative so the only possible answer is w = 5/2.

if w = 5/2, then

p = 2w-3 = 5-3 = 2

we have:

p = 2

w = 5/2

p = 2l + 2w gets p = 4 + 5 = 9

the perimeter of the first board is 9 feet.

since the perimeter of the second board is 1/5 the perimeter of the first board, the perimeter of the second board is 9/5.

to see if that's correct, we substitute known values for l and w into the second board.

the length of the second board is 1/l.

this becomes 1/2.

the width of the second board is 1/w

this bgecomes 1/(5/2) = (2/5)

let l2 = length of second board.

let w2 = width of second board.

l2 = (1/2)

w2 = (2/5)

let p2= perimeter of second board.

then p2 = 9/5

since p2 = 2*l2 + 2*w2, we should get p2 = 9/5 using the dimensions of l2 and w2.

2 * l2 = 2 * (1/2) = 1

2 * w2 = 2 * (2/5) = 4/5

1 is the same as 5/5

5/5 + 4/5 = 9/5

p2 checks out good.

the dimensions as given are good.

answer to the problem is:

perimeter of the first rectangular board is 9 feet.

the height of the surface increases from the center out to the sides of the road.

step-by-step explanation:

as we move out we move away from the x-axis.

and as mentioned in the problem statement that height of a road increases when we move away from the center x.

hence proved that 3rd option

the height of the surface increases from the center out to the sides of the road.

is the correct option.