Write the slope intercept form of the equation that passes through the point (-2,3) and is parallel to the line y= -6x -9 y=-6 - 9 y=-6 - 1 y=6x - 9 y=1/6x - 1

y = -6x -9

Step-by-step explanation:

Slope intercept form: y=mx + b

Point slope form: y-y1 = m(x-x1)

The slope is -6

So, plug in the slope for m and (-2,3) for x and y.

y-3 = -6(x-(-2)

or

y - 3 = -6(x + 2)

Now distribute,

y - 3 = -6x - 12

Simplify by isolating y and adding 3 to both sides of the equation

y - 3 = -6x - 12

  +3          + 3

y = -6x - 9

This is now in slope intercept form y = mx + b

if you need , reply with more info. u.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°