Hich function has a range of {y|y ≤ 5}? f(x) = (x – 4)2 + 5 f(x) = –(x – 4)2 + 5 f(x) = (x – 5)2 + 4 f(x) = –(x – 5)2 + 4

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

where

(h,k) is the vertex of the parabola

if a>0 -----> the parabola open upward (vertex is a minimum)

if a<0 -----> the parabola open downward (vertex is a maximum)

Verify each case

case A)

The vertex is the point

a>0 -----> the parabola open upward (vertex is a minimum)

The range is the interval--------> [5,∞)

case B)

The vertex is the point

a<0 -----> the parabola open downward (vertex is a maximum)

The range is the interval--------> (-∞,5]

case C)

The vertex is the point

a>0 -----> the parabola open upward (vertex is a minimum)

The range is the interval--------> [4,∞)

case D)

The vertex is the point

a<0 -----> the parabola open downward (vertex is a maximum)

The range is the interval--------> (-∞,4]

a orange at the grocery store idk what other product that could be

d no solution

step-by-step explanation: