Dolores made two isosceles right triangles by cutting the square along its diagonal. she says she can find the area of one of the triangles by using the formula for the area of the square, and then dividing the answer by 2. do you agree? explain.

  Yes, I agree. The explanation is given below.

Step-by-step explanation:  As given in the question, a square ABCD is shown in the attached figure. Dolores cut the square along its diagonal BD and made two isosceles right angled triangles ΔABD and ΔCBD.

We need to show the area of triangles ABD and CBD are equal, and half of the area of square ABCD, i.e.,

area of ΔABD = are of ΔCBD = half of area of square ABCD.

Now, in ΔABD and ΔCBD, we have

AB = CD,

AD = BC

and BD is the common side.

Therefore, by sing SSS (side-side-side) postulate, we get

ΔABD ≅ ΔCBD.

So, area of ΔABD = area of ΔCBD.

Now, area of square ABCD =  area of ΔABD + area of ΔCBD

                                              = 2 × area of ΔABD

                                              = 2 × area of ΔCBD.

Thus, Doroles is absolutely correct in finding the area of any one of the triangles by using the formula for the area of the square and then dividing by 2.

Hence explained.

assuming you mean addition: addition and subtraction are reverse operations.

step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.