(75 points) asap use a system of equations to solve this problem. bronze is a mix, or alloy, of tin and copper. a metal worker needs 100 g of bronze that is 25% tin. he has one tin/copper alloy that is 5% tin and another tin/copper alloy that is 45% tin. let x = the number of grams of the 5% tin alloy. let y = the number of grams of the 45% tin alloy. how many grams of each alloy should the metal worker combine? enter your answers in the boxes.

50 grams of 45% alloy and 50 grams of tin alloy

Step-by-step explanation:

Those are the two equations:

x+y=100

the sum of the weight of both alloys is 100 g

0.5x+0.45y=0.25*100

the sum of the weights of tin has to be 25% of 100g, which is actually 25 g

0.5x+0.45y=25

So we have:

x+y=100

0.5x+0.45y=25

x=10-y

0.5x+0.45y=25

We substitute:

0.5(10-y)+0.45y=25

We calculate:

5-0.5y+0.45y=25

-0.5y+0.45y=20

0.4y=20

4y=200

y=50

So he needs 50 grams of 45% alloy and 100-50=50 grams of tin alloy as well

step-by-step explanation:

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