Identify the vertex and the y- intercept of the graph of the function , i would appreciate the you

Vertex (-3, 4); y-intercept: -5.

Step-by-step explanation:

y = -(x + 3)^2 + 4

This is the vertex form of a quadratic function whose general form is:

y = a(x - b)^2 + c    where the vertex is at (b, c).

So comparing this last equation to the one in the question we see that the vertex is at (-3, 4).

When the graph passes through the y-axis x = 0 so the y intercept is calculated as follows:

y =  - (0 + 3)^2 + 4

y =  -9 + 4 = -5.

so the y-intercept is at (0, -5)

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11