Qand r are not mutually exclusive events. if p(q) = 0.12, p(r)= 0.25 and p(q and r)=0.03, find p(q or r)

P (Q or R) = 0.34

Step-by-step explanation:

We are given that Q and R are not mutually exclusive events. Also, the following probabilities are given:

P(Q) = 0.12, P(R)= 0.25 and P(Q and R)=0.03

We are to find the probability P(Q or R). Since mutually exclusive events mean that they cannot occur simultaneously, so we will use the formula:

P (Q ∪ R) = P (Q) + P (R) - P (Q ∩ R)

P (Q ∪ R) = P (Q or R)

P (Q or R) = 0.12 + 0.25 - 0.03 = 0.34

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation: