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Mathematics, 24.06.2019 23:00 196336

Select from the drop-down menus to correctly complete the proof. to prove that 3√2 is irrational, assume the product is rational and set it equal to a/b , where b is not equal to 0: 3√2=a/b . isolating the radical gives √2=a/3b . the right side of the equation is choose (rational or irrational) . because the left side of the equation is choose (rational or irrational) , this is a contradiction. therefore, the assumption is wrong, and the number 3√2 is choose (rational or irrational).

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Select from the drop-down menus to correctly complete the proof. to prove that 3√2 is irrational, a...
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