Which is the solution for log(4x-1)=log(x+1)+log2?

x = 1.5

Step-by-step explanation:

Solution

log(4x - 1) - log(x+1) = log2        log(x + 1) was subtracted from both sideslog[(4x - 1)/log(x+1)] = log2        Subtaction of logs means division  (4x - 1) / (x + 1) = 2                      Take the antilog of both sides4x - 1 = 2(x + 1)                           Remove the brackets 4x - 1 = 2x + 2                            Add 1 to both sides4x = 2x + 3                                 Subtract 2x  4x - 2x = 3                                  2x = 3                                         Divide by 2 x = 3/2                                        Answer

Check

Left Hand Side

log(4*1.5 - 1) log(6 - 1)log(5)

Right Hand Side

log(1.5 + 1) + log(2)log(2.5) + log(2)log2*2.5log 5

And they check