Find the angles of the rhombus if the ratio of the angles formed by diagonals and the sides of the rhombus is 6: 5.

Angles are and

Step-by-step explanation:

Here, the ratio of the angles formed by diagonals and the sides of the rhombus is 6:5.

Let the  angles formed by diagonals and the sides of the rhombus are 6x and 5x.

Where x is any number.

Thus, By the property of rhombus,

Diagonals perpendicularly bisect each other.

Therefore,

⇒

⇒

⇒

Therefore, the  angles formed by diagonals and the sides of the rhombus are and

⇒ The angles of rhombus are   and  

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a