Find the coordinates of the vertices after the reflection across the x axis and then across the y axis.

  A'(2, -3), B'(-3, -4), C'(-2, 0)

Step-by-step explanation:

Reflection across each of the axes is equivalent to reflection across their point of intersection, (0, 0). Such a reflection negates both the x- and y-coordinates of the original point.

  A' = -A = -(-2, 3) = (2, -3)

  B' = -B = -(3, 4) = (-3, -4)

  C' = -C = -(2, 0) = (-2, 0)

yes

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3