Me .find the coordinates of j' after a reflection across the line x=1 and then across the x axis.

  J'' = (0, 1)

Step-by-step explanation:

For M being the midpoint of the segment JJ', its coordinates are the average of those of J and J':

  M = (J + J')/2

We can rearrange this to find J' from M and J.

  2M = J + J'

  J' = 2M - J

For a reflection across the line x = 1, the x-coordinate of M is 1. For a reflection across the line y = 0 (the x-axis), the y-coordinate of M is 0. Your double reflection amounts to a reflection across the point (1, 0).

The the image of J after the two reflections is ...

  J' = 2(1, 0) -(2, -1) = (2·1-2, 2·0+1)

  J' = (0, 1)

_____

In the attached image, the point after the second reflection is called J".

part a

in a city ice cream is mostly only bought when the temperature is very high as ice cream cools down our

so we can derive the conclusion that as the temperature increases the number of ice creams sold also increases

part b

y intercept is 5

slope is 2

happy to

pls mark as brainliest