The area of a rectangle is 45 cm2. two squares are constructed such that two adjacent sides of the rectangle are each also the side of one of the squares. the combined area of the two squares is 106 cm². find the lengths of the sides of the squares.

9cm and 5 cm

Step-by-step explanation:

Given that area of rectangle = lw = 45 cm square...i

where l =length and w = width

First square has side l and second side w

Area of two squares combined = sum of their areas

=

Substitute in II equation

\\2025+w^4-106w^2=0\\(w^2-25)(w^2-81)=0\\w=5 or 9\\l=9 or 5" alt="(\frac{45}{w} )^{2}+w^{2} =106cm^2...iiEliminate l from I equationl =[tex]\frac{45}{w}" />

Substitute in II equation

\\2025+w^4-106w^2=0\\(w^2-25)(w^2-81)=0\\w=5 or 9\\l=9 or 5" />[/tex]

So  length of rectangle = 9 cm and width = 5 cm

step-by-step explanation:

what grade level is this? need to know so i can look in my old textbooks!