Julian jogs 2 kilometers east, 4 kilometers north, and then 7 kilometers west. how far is julian from his starting position, to the nearest tenth of a kilometer?

6.4 kilometer

==============================

Step-by-step explanation:

See the attached figure.

Let Julian starts from point O (0,0)

Julian jogs 2 kilometers east ⇒ arrived to point A (2,0)

4 kilometers north ⇒ arrived to point B (2,4)

and then 7 kilometers west ⇒ arrived to point C (-5,4)

How far is Julian from his starting position?

So, it is required to find the distance OC

From the graph OC =

So, the distance from his starting position ≈ 6.4 km (to the nearest tenth of a kilometer)

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.