Triangle pqr is transformed to similar triangle p’q’r’: what is the scale factor of dilation? 1 over 2 1 over 3 1 over 4 1 over 5

1 over 2

Step-by-step explanation:

Triangle ABC has sides 2,2,2√2

Triangle A'B'C' has sided 1,1,√2

Scale (dilation) factor is less than one because A'B'C' is contracted not dilated. To get A' from A, multiply by 1/2.

The scale factor of dilation is:

                   1 over 2

The scale factor of dilation is the ratio of the length of the sides of the new triangle to the length of the corresponding sides of the original triangle.

Length of the side BC in original triangle is:

           BC= 2 units

and the length of the side B'C' in the transformed triangle is:

             B'C'= 1 units

Hence, the scale factor of the dilation is:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

the first one, all those points on the line just make a strait line.