Enter the correct answer in the box. use the sum of cubes identity to find the factors of the expression 8x^6 + 27y^3

(2x^2 + 3y)(4x^4 - 6x^2y + 9y^2).

Step-by-step explanation:

a^3 + b^3 = (a + b)(a^2 - ab + b^2)  is the identity.

Comparing this with the sum in the question:

a = 2x^2 and b = 3y so we have:

8x^6 + 27y^3 = (2x^2 + 3y)(4x^4 - 2x^2*3y + 9y^2)

= (2x^2 + 3y)(4x^4 - 6x^2y + 9y^2).

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step-by-step explanation:

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse