Brad has two alloys containing copper and silver. alloy a contains 50% pure silver, and alloy b contains 75% pure silver. he wants to make 10 ounces of a new alloy containing 70% pure silver. how much alloy of each type does he need to mix?

There are 2 ounces of 50% silver

There are 8 ounces of 75% silver

Step-by-step explanation:

The percentage of silver times the amount of silver + the percentage of silver times the amount of silver = The percentage of silver times the  total amount of silver

We will put A in the first spot and B in the second spot  and The total on the right

We will take x ounces of A at 50%

We need 10 ounces of the total

10-x  is the amount we need for B  (  The amount in A Plus the amount in B has to equal 10)

We have (10-x) at 75% for B

We have 10 ounces at 70% for The total

 .50 *x + .75*(10-x) = .70*10

.5x +  .75*(10-x) = 7

Distribute

.5x +7.5 - .75x =7

Combine like terms

-.25x + 7.5 = 7

Subtract 7.5 from each side

-.25x +7.5-7.5 =7-7.5

-.25x =-.5

Divide by -.25 on each side

-.25x/-.25 = -.5/-.25

x =2

There are 2 ounces of 50% silver

To find how many ounces of 75% silver

10-x = 10-2 = 8

There are 8 ounces of 75% silver

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .