Two column proof: if a kite is inscribed in a circle, then one of the diagonals of a kite is a diameter of the circle. detailed explanation , i want to be able to understand this thoroughly. diagram is attached, in advance!

Given : BRDG is a kite that is inscribed in a circle,

With BR = RD and BG = DG

To prove : RG is a diameter

Proof:

Since, RG is the major diagonal of the kite BRDG,

By the property of kite,

∠ RBG = ∠ RDG

Also, BRDG is a cyclic quadrilateral,

Therefore, By the property of cyclic quadrilateral,

∠ RBG + ∠ RDG = 180°

⇒ ∠ RBG + ∠ RBG = 180°

⇒ 2∠ RBG = 180°

⇒ ∠ RBG = 90°

⇒ ∠ RDG = 90°

Since, Angle subtended by a diameter or semicircle on any point of circle is right angle.

⇒ RG is the diameter of the circle.

Hence, proved.

41*67/2=1373.5

step-by-step explanation:

i just used a calculator

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)