Two cards are chosen at random from a standard deck of 52 cards without replacement. what is the probability of choosing two kings?

1/221

Step-by-step explanation:

There are 4 kings in a standard deck of cards

P( one king) =  number of kings/ number of cards

                        4/52

                          = 1/13

Then we do not put the card back.  Now we have 3 kings and 51 cards

P(2nd king) = number of kings/ number of cards

                     =3/51

                       =1/17

We need to multiply these together

P( one king, 2nd king without replacement) = 1/13*1/17 = 1/221

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130