What are the real zeros in f(x)=x^3+8

-2

Step-by-step explanation:

f(x)=x^3+8

Set it equal to 0

0 = x^2 +8

Subtract 8 from each side

-8 = x^3+8-8

-8 = x^3

Take the cube root of each side

-8 ^ 1/3 = x^3 ^ 1/3

-2 = x

The only real root is -2

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step-by-step explanation:

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the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: