Aflorist currently sells 49000 bouquets per year at a cost of 10 dollars each. in the previous year when they raised the price to 14 dollars, they only sold 35000 bouquets that year. assuming the amount of bouquets sold is in a linear relationship with the cost, what is the maximum revenue?

490000 dollars.

Step-by-step explanation:

Revenue is equal to the number of bouquets sold multiplied by the price per bouquet :

For 49000 bouquets sold at 10 dollars each, the revenue is:

For 35000 bouquets sold at 14 dollars each, the revenue is:

Thus the maximum revenue is 49000 dollars.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)